[DEVILSAN]

Somebody Please help me answer these question with supporting explanation.

Here are few PG Entrance test questions Objective Type.

Q.1 if the code segment points at address x and the program counter has value y , then the next instruction will be fetched from

options are

(A) xy
(B)x+2y
(C)2x+y
(D)x+y

Answer with explanation:

Q.2 What is the output of the following recursive procedure when called as A(125,15) ?procedure A(x,y)
if y=0 then return (x)
Else return (A(y,x mod y))
endif
end A

options are
(A)10
(B)125
(C)5
(D)25

Answer with explanation:


Q.3 With an IP address of 201.141.20.10 which of the following is the default subnet mask?

options are
(A)0.0.0.0
(B)255.255.0.0
(C)255.255.255.0
(D)255.255.0.0

Answer with explanation:



You are welcomed

[emolamol]

hi devilsan,
i think i know the answer of 1st 2 question


1)answer is (d)i.e x+y

the reason is if y is the relative address of the next instruction in the program then after adding it with x(vich is the absolute address of the memory location where program starts.)..x+y becomes the absolute address the next instruction to be fetched.

2)answer is (c)i.e 5

this code is to find the GCD of two numbers.
and GCD(125,15)=5

[DEVILSAN]

Well Done Amol

[Weaver]

With your first question you should indicate which ISA you are referring to. Logic would say x86 due to its popularity and the segmented memory model, but it is always better to specify. Now on to question 3.

3) C

The leading octet of the IP is '201', which puts it as a Class C address (ignoring any CIDR).

0 - 127 = Class A
128 - 191 = Class B
192 - 223 = Class C

Since it is a Class C, the subnet mask would be 255.255.255.0 or 'C'

-Weaver

[DEVILSAN]

even i thought the same way weaver